Physics route · lesson 1 of 5
  1. 01Measurement and uncertaintyUnseen
  2. 02Motion and interactionUnseen
  3. 03Energy and conservationUnseen
  4. 04Waves and informationUnseen
  5. 05Fields, models, and limitsUnseen

Physics / Field trial lesson 01

Measurement and uncertainty

Turn an instrument reading into an honest claim by naming the method, separating scatter from offset, and reporting only the precision the evidence supports.

Study time
Awaiting learner observation
Evidence
Unseen
Candidate
0.1-foundations-candidate
Review
Named human reviews pending
Field-trial contentComplete enough to test; not published as reviewed Foundations curriculum.
01 / Orient

A reading becomes evidence only when the procedure travels with it

“The period is 2.4” is not yet a physical result. Which event started the timer? Which event stopped it? Was one swing or ten swings timed? What unit did the display use? What was the instrument's smallest step? Could another observer repeat the same procedure?

Measurement connects a phenomenon to a comparison standard through an operation. The reported number is therefore a claim about the phenomenon, the instrument, and the method together. Leaving out the unit or uncertainty does not make the measurement cleaner; it hides part of what is known.

x = x̂ ± u, with unit and uncertainty convention stated
The interval communicates the measurement's supported precision. The uncertainty estimate is not universal; its meaning depends on the stated method and confidence convention.
Check your model

Five length readings span from 14.2 cm to 14.6 cm. Using half the range as the uncertainty convention, what uncertainty should be reported?

Unseen

Enter the uncertainty magnitude and a centimetre unit.

02 / Model

Repetition shows scatter; a reference exposes offset

Repeated trials can reveal how much a procedure varies. A tight cluster is precise; a broad cluster is less precise. But the cluster's centre may still be displaced from an accepted reference. That displacement is a discrepancy and can arise from a shared calibration offset or another systematic effect.

Repetition alone cannot diagnose every shared offset because the same shift can affect every trial. To test accuracy, compare with a defensible reference, reverse the method when possible, or use an independent instrument or calibration procedure.

reference 10.0 cmPrecise + accurateScattered + centredPrecise + offset
Precision and accuracy answer different questionsFigure 1. Horizontal position shows measured length; each mark is one trial. The vertical rule is the accepted reference.
Read the figure description

Plot A has closely packed measurements centred on 10.0 centimetres and is both precise and accurate. Plot B has measurements spread from 9.6 to 10.4 centimetres but centred near 10.0, so it is less precise while its centre is accurate. Plot C has closely packed measurements near 10.5 centimetres, so it is precise but discrepant from the 10.0-centimetre reference.

What each diagnostic can and cannot reveal
DiagnosticEvidence it providesBlind spot
Read the smallest display or scale stepInstrument resolutionDoes not expose calibration offset
Repeat the same procedureTrial-to-trial scatter and repeatabilityA shared shift may remain hidden
Measure a trusted referenceDiscrepancy from the referenceReference itself has uncertainty
Change observer or methodSensitivity to procedural choicesNew method may add different effects
Check your model

Which diagnostics can reveal a constant +0.5 cm zero offset? Select every defensible choice.

Unseen

Select methods that compare the instrument or procedure with independent information.

Answer choices
Check your model

A tight cluster of measurements lies far from an accepted reference. Which two-word description fits it?

Unseen

Enter the description using the words precise and inaccurate.

03 / Formalize

Compute a summary without pretending it is the whole experiment

Worked example

Worked example — report repeated timing trials

Five period measurements are 2.38 s, 2.42 s, 2.39 s, 2.41 s, and 2.40 s. Use the mean as the best estimate and half the range as a simple uncertainty convention.

  1. Add the five values to obtain 12.00 s, then divide by 5. The mean is 2.400 s.
  2. Find the range: 2.42 s minus 2.38 s equals 0.04 s.
  3. Half the range is 0.02 s. State explicitly that half-range, not a standard deviation or confidence interval, is the chosen convention.
  4. Round the best estimate to the same decimal place as the uncertainty.
  5. Report 2.40 plus or minus 0.02 s using the stated repeated-timing procedure.

ConclusionThe result is 2.40 ± 0.02 s, where 0.02 s is half the observed range. It summarizes repeatability but does not rule out a shared timer offset.

percent uncertainty = (u / |x̂|) × 100 percent
The numerator and denominator must use the same unit, so the ratio is dimensionless. Percent uncertainty compares uncertainty relative to the measured magnitude.

Worked example

Worked example — decide whether a stopwatch can separate two results

A stopwatch has stated uncertainty ±0.05 s. Two sprint times are 12.04 s and 12.07 s. Can the display alone support the claim that the second runner was 0.03 s slower?

  1. Compute the displayed difference: 12.07 s minus 12.04 s equals 0.03 s.
  2. Compare that difference with the stated uncertainty scale of 0.05 s for each timing.
  3. The difference is smaller than even one timing's stated uncertainty, so the intervals overlap substantially.
  4. Extra decimal places in the display do not reduce the stated uncertainty.

ConclusionThese readings do not support a confident ordering at a 0.03 s separation with this uncertainty. The limitation belongs in the conclusion.

04 / Experiment

Hide an offset inside a convincing cluster

Prediction before motion

Hold scatter fixed and increase the hidden zero offset. Predict what happens to the cluster width, cluster centre, precision, and accuracy before revealing the reference.

Invariant
Repetition changes the estimate of the cluster and its scatter; a constant zero offset shifts every trial and is only identifiable against a reference or independent calibration.
Observe
Run repeated trials, then reveal the reference. Which feature diagnosed scatter and which comparison exposed the shared offset?
Static account
For a true value of 10.0 cm, low scatter with zero offset produces a tight cluster near 10.0 cm. The same scatter with a +0.5 cm offset produces an equally tight cluster near 10.5 cm. Precision is similar; accuracy is not.
05 / Transfer

Design a comparison that can fail honestly

The transfer task asks you to compare two pendulum periods. A useful design identifies the start and stop events, times multiple cycles to reduce reaction-time influence, repeats trials, states a summary and uncertainty convention, and checks for at least one systematic effect such as timer calibration or inconsistent release angle.

A strong conclusion is conditional. It says what the measurements distinguish at the achieved uncertainty and what remains unresolved. That is not weakness; it is the boundary that makes the claim trustworthy.

Transfer task

You compare two pendulums whose mean periods differ by 0.03 s, while each repeated result is reported with ±0.05 s uncertainty. Which conclusions are supported? Select every defensible statement.

Unseen

Select statements that respect the reported uncertainty and identify a useful next step.

Answer choices